JEE Main 2025 Merit List: How NTA Prepare the List After Exam?

2 min read

Aparajita Debnath

Content Writer | Updated on - Apr 16, 2025

JEE Main Session 2 concluded on April 9, 2025, after being held on April 2-4 and 7-9. Paper 1 (B.E/B.Tech) took place on April 2-4 and 7-8, with Paper 2 (B.Arch/B.Plan) on April 9.

Kolkata: Candidates who appeared for both JEE Main 2025 sessions will have their best overall NTA score considered for subsequent stages of the admission process. The provisional JEE Main 2025 Session 2 answer key has just released by the National Testing Agency. Following the objection period, the final results and ranks for the JEE Main Session 2 exams will be announced soon by the agency.

For B.E/B.Tech candidates in JEE Main 2025, the NTA scores from both Session 1 and Session 2 will be combined to generate the overall merit list and rankings. If a candidate took both sessions, their highest total NTA score will be used for further processing.

In the event of a tie in the total NTA score in JEE Main 2025 for two or more candidates, their relative ranking will be decided based on the established 'Method of resolving ties'. Similarly, for Paper 2A (B.Arch) and Paper 2B (B.Plan), NTA scores from both JEE Main 2025 sessions will be merged to create the overall merit list and rankings. The best total NTA score from either session will be used for candidates who appeared in both. Tie-breaking for these papers will also follow the 'Method of resolving ties'.

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Frequently Asked Questions

Ans: If a candidate appears for both sessions, their best NTA score out of the two sessions will be considered for the preparation of the merit list and ranking.

Ans: No, NTA merges the NTA scores from both Session 1 and Session 2 to prepare a single overall merit list.

Ans: In case two or more candidates obtain the same total NTA score, the inter-se merit is determined using a tie-breaking policy which considers:

Higher NTA score in Mathematics.
Higher NTA score in Physics.
Higher NTA score in Chemistry.
Lower ratio of incorrect to correct answers across all subjects.
Lower ratio of incorrect to correct answers in Mathematics.
Lower ratio of incorrect to correct answers in Physics.
Lower ratio of incorrect to correct answers in Chemistry.

Ans: Currently, the JEE Main merit list is solely based on the NTA scores obtained in the JEE Main examination. However, for admission to NITs, IIITs, and CFTIs, candidates also need to meet a certain percentage in their Class 12 exams (currently 75% for general category and 65% for reserved categories).

Ans: Yes, NTA prepares separate category-wise merit lists based on the NTA scores, in addition to the overall merit list.

Ans: No, the normalization is primarily done across the different sessions to account for varying difficulty levels. Within a single session, the percentile is calculated based on the raw scores of the candidates in that session.

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